Program :
WAP find a Leap Year in Java
import java.util.*;
import java.util.Scanner;
class LeapYr{
public static void main(String args[]){
// Enter Year we want to check
System.out.println("Enter Random Year Check for Leap:- ");
Scanner sc = new Scanner(System.in);
int year = sc.nextInt();
// if year is divisible by 4, it is a leap year.
if((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0))){
System.out.println("Year " + year + " is a leap Year");
}
else{
System.out.println("Year " + year + " is a not leap Year");
}
}
}
Answer:
Enter Random Year Check for Leap:-
2025
Year 2025 is a not leap Year
Enter Random Year Check for Leap:-
2020
Year 2020 is a leap Year
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